OK so I am in the throws of balancing the Eldo crank. Too much fun.
I've read to add 28 grams to the rotating weight to compensate for oil in the journal.
I've also heard that one takes 50% of that oil weight into consideration when determining the bob weight.
So... I gotta know:
do I:
Determine the rotating weight (large end of con rods, with bearings) PLUS 28 grams (oil compensation). =Rot
Multiply the rotating weight by 52%
Determine recipricating weight (con rods small end, bushings, pistons, pins, rings, pin clips).
=Rec
add the 52% plus the recipricating weight.
.52(rot+28g)+Rec=Bob Weight
or
Do I divide the oil compensation by 2 (for some reason). I have been told that the oil compensation is divided by 2...
.52(rot+(28g/2))+Rec = BW
Or have I got this all back asswards?
No one said there would be math involved... heh heh
Alex
I've read to add 28 grams to the rotating weight to compensate for oil in the journal.
I've also heard that one takes 50% of that oil weight into consideration when determining the bob weight.
So... I gotta know:
do I:
Determine the rotating weight (large end of con rods, with bearings) PLUS 28 grams (oil compensation). =Rot
Multiply the rotating weight by 52%
Determine recipricating weight (con rods small end, bushings, pistons, pins, rings, pin clips).
=Rec
add the 52% plus the recipricating weight.
.52(rot+28g)+Rec=Bob Weight
or
Do I divide the oil compensation by 2 (for some reason). I have been told that the oil compensation is divided by 2...
.52(rot+(28g/2))+Rec = BW
Or have I got this all back asswards?
No one said there would be math involved... heh heh
Alex